Question 20435: Hi.This word problem is basic, but I'm stumped. Coins in a bank are all dimes, nickels, and quarters. There are twice as many dimes as quarters, and two more nickels than quarters. If the total value of the coins is $7.60, how many coins are in the bank? This is what I have so far. Q = 2(d) N = 2d =2, so
760 cents = 25(2d) + 10(d) + 5(2d+2)
50d+10d+10d+2
70d+2=760
70d=758
I think you can see I have a problem. Any help you could give me would be appreciated. Thanks!!!!
Answer by wuwei96815(245)   (Show Source):
You can put this solution on YOUR website! This is a two step problem. First, we have to write expressions that define the number of each type of coin. Then, we have to write an equation that expresses the values that each of theses coins represents.
First:
x=number of quarters
2x=numbre of dimes
x+2=number of nickles
Second:
$0.25(x) + $0.10(2x) + $0.05(x+2) = $7.60
.25x + .10x +.05x + .10 = 7.60
.50x = 7.60 - .10 = 7.50
x = 15
2x = 30
x+2 = 17
You can check the correctness of these answers by going back and substituting them in the equation.
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