SOLUTION: Solve the problem. Use 3.14 as an approximation for π where appropriate. Find the volume of a tent having the shape of a rectangular solid of length 15 ft, width 15 ft, and

Algebra ->  Volume -> SOLUTION: Solve the problem. Use 3.14 as an approximation for π where appropriate. Find the volume of a tent having the shape of a rectangular solid of length 15 ft, width 15 ft, and      Log On


   

Question 204157: Solve the problem. Use 3.14 as an approximation for π where appropriate.
Find the volume of a tent having the shape of a rectangular solid of length 15 ft, width 15 ft, and height 9 ft topped by a rectangular pyramid of the same width and length with height 8 ft. (Round to the nearest hundredth unit.)
Thank you tutors for all your help and time.
Found 2 solutions by nerdybill, Theo:
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Consider the two shapes separately that makes up the tent:
- volume of rectangle -- L*W*H
- volume of triangular prism -- (1/2)BHL
reference:
http://www.mathsteacher.com.au/year9/ch14_measurement/19_prism/prism.htm
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volume of rectangle:
L*W*H = 15*15*9 = 2025 cubic feet
.
volume of triangle:
(1/2)BHL = (1/2)15*8*15 = 900 cubic feet
.
Total volume = 2025+900 = 2925 cubic feet

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
volume of the tent is the volume of the rectangular solid plus the volume of the rectangular pyramid on top of it.
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volume of rectangular solid is length * width * height = 15 * 15 * 9
volume of rectangular pyramid is 1/3 * length * width * height = 1/3 * 15 * 15 * 8
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your answer should be:
2025 + 600 = 2625 cubic feet.
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there is no pie involved.
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