Question 204067: joe has twice as many quarters than dimes in total joe has 9 dollars how many coins of each does joe have
Found 2 solutions by RAY100, PRMath:
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! Let D = # dimes,,,,and Q= # quarters
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Q=2D
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25Q + 10D =900
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25(2D) +10D=900
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50D+10D=60D=900
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D=15,,,,,,Q=30
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check,,,15*10 +30*25 =900
150 +750 = 900,,,ok
Answer by PRMath(133) (Show Source):
You can put this solution on YOUR website! joe has twice as many quarters than dimes in total joe has 9 dollars how many coins of each does joe have
The coins together will add up to $9.00 yes?
So... let's make an equation using "D" for Dimes and "Q" for Quarters, but remember there are TWICE as many quarters as dimes. That will translate to.....
D(.10) + 2D(.25) = 9.00 <----Here is our equation....
.10D + .50D = 9.00 (see how we multiplied .10 times D and multiplied 2D times .25?)
.60D = 9.00 (added like terms)
D = 15 (divide both sides by .60)
Therefore you have 15 dimes. If you have twice as many quarters as those 15 dimes, then you have 2 times 15 which is 30 quarters.
Soooo, does this add up to 9.00?
Let's see:
15 dimes equals: $1.50
30 quarters equals: $7.50
TOTAL: $9.00
It works. I hope this helps.
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