SOLUTION: If the inspection division of a county weifhts and measures department wants to estimate the mean amount of soft-drink fill in 2-liter bottles to with +/- 0.01 liter with 95% confi
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Question 203867: If the inspection division of a county weifhts and measures department wants to estimate the mean amount of soft-drink fill in 2-liter bottles to with +/- 0.01 liter with 95% confidence and also assumes that the standard deviation is 0.05 liter, what sample size is needed? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! If the inspection division of a county weights and measures department wants to estimate the mean amount of soft-drink fill in 2-liter bottles to within +/- 0.01 liter with 95% confidence and also assumes that the standard deviation is 0.05 liter, what sample size is needed?
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Since E = z
sqrt(n) = z
n = [z*s/E]^2
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Your Problem:
n = [1.96*0.05/0.01]^2
n = 96.04
Rounding up you get n = 97 (this is the required sample size)
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Cheers,
Stan H.
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