SOLUTION: How do I solve log(2x + 1) – log(x + 4) =0 ?

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Question 203804: How do I solve log(2x + 1) – log(x + 4) =0 ?
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
log%28%282x%2B1%29%29-log%28%28x%2B4%29%29+=+0 Apply the quotient rule for logarithms: log%28%28M%29%29-log%28%28N%29%29+=+log%28%28M%2FN%29%29
log%28%28%282x%2B1%29%29%2F%28%28x%2B4%29%29%29+=+0 Express this in exponential form: Log%5Bb%5D%28x%29+=+y means b%5Ey+=+x
10%5E0+=+%28%282x%2B1%29%2F%28x%2B4%29%29 Substitute 10%5E0+=+1
1+=+%28%282x%2B1%29%2F%28x%2B4%29%29 Multiply both sides by (x+4)
x%2B4+=+2x%2B1 Subtract x from both sides.
4+=+x%2B1 Subtract 1 from both sides.
3+=+x or highlight%28x+=+3%29