Question 203793: I am so confused on (ln) & (logs) & (e)....
problem
10^(t^2-t)=100
what does this mean? and how do i solve?
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! 10^(t^2-t) = 100 = 10^2
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This can be solved without logs by setting exponents equal
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t^2-t=2
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t^2 -t -2 =0
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(t-2)(t+1) =0
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t= 2, -1
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check
(t=2),,10^2 = 100,,,,ok
(t=-1),,,,10^2 = 100,,,,ok
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