Question 203748: Product of two consecutive integers is 6 less than 6 times their sum. Find the integers
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! Let x = first integer,,,,(x+1) = 2nd integer
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x(x+1) = 6 {x+(x+1)} -6
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x^2 +x = 12x +6-6
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x^2 -11x =0
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x (x-11)=0
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x=0,,11,,,,0,1,,,,,,11,12
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check
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(x=11,12),,11*12 = 6(11+12) -6
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132 = 6*23-6 = 138-6=132,,,,ok
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(x=0,1), 0*1 = 6(1) -6,,,,0=0,,,,ok
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