Question 203715This question is from textbook College Algebra
: Identify the vertex and intercepts of the graph f y=x^2+4x+3
This question is from textbook College Algebra
Answer by tina_wood(5)   (Show Source):
You can put this solution on YOUR website! f(x)= x^2+4x+3
to find the vertex, use (-b/2a)
-4/2(1) = -4/2 = -2 This is the x part of the vertex (-2,?), then we use -2 in place of x in f(x)
f(-2) = (-2)^2+4(-2)+3
= 4-8+3
= -1
Therefore the vertex is (-2,-1)
To find the x - intercepts, you set the equation to equal 0
x^2+4x+3=0 (does it factor?)
(x+3)=0, (x+1)=0
x= -3, x=-1
To find the y-intercepts, let x=0
x^2+4x+3
(0)^2+4(0)+3
y=3
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