SOLUTION: please help. division of rational expressions. 6s^2+st-2t^2 / 6s^2-5st+t^2 divided by. 3s^2+17st+10t^2/6s^2+13st-5t^2 i hope that makes sense. i pretty much understand the concept

Algebra ->  Rational-functions -> SOLUTION: please help. division of rational expressions. 6s^2+st-2t^2 / 6s^2-5st+t^2 divided by. 3s^2+17st+10t^2/6s^2+13st-5t^2 i hope that makes sense. i pretty much understand the concept       Log On


   

Question 203584This question is from textbook intermediate algebra
: please help. division of rational expressions. 6s^2+st-2t^2 / 6s^2-5st+t^2 divided by. 3s^2+17st+10t^2/6s^2+13st-5t^2 i hope that makes sense. i pretty much understand the concept and how i have to first factor out the expressions and than divide the first expression by the reciprocal of the second expression but im getting a different answer from the correct answer This question is from textbook intermediate algebra

Found 2 solutions by scott8148, jim_thompson5910:
Answer by scott8148(6628) About Me  (Show Source):
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[(3s + 2t)(2s - t) / (3s - t)(2s - t)] / [(3s + 2t)(s + 5t) / (3s - t)(2s + 5t)]

[(3s + 2t) / (3s - t)] * [(3s - t)(2s + 5t) / (3s + 2t)(s + 5t)]

(2s + 5t) / (s + 5t)

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Start with the given expression.


Multiply the first fraction %286s%5E2%2Bst-2t%5E2%29%2F%286s%5E2-5st%2Bt%5E2%29 by the reciprocal of the second fraction %283s%5E2%2B17st%2B10t%5E2%29%2F%286s%5E2%2B13st-5t%5E2%29.


Factor 6s%5E2%2Bst-2t%5E2 to get %283s%2B2t%29%282s-t%29.


Factor 6s%5E2-5st%2Bt%5E2 to get %283s-t%29%282s-t%29.


Factor 6s%5E2%2B13st-5t%5E2 to get %282s%2B5t%29%283s-t%29.


Factor 3s%5E2%2B17st%2B10t%5E2 to get %28s%2B5t%29%283s%2B2t%29.


Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


%282s%2B5t%29%2F%28s%2B5t%29 Simplify.


So simplifies to %282s%2B5t%29%2F%28s%2B5t%29.


In other words,