Question 203483: solve:
log x^2= (log x)^2
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! log(x^2) = (logx)^2,,,,remember loga^b=b*log a
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2logx = logx * logx
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2 logx -logx*logx =0
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factor
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If 2a-a^2=0,, we would factor,,,a(2-a)=0
Then we would set,,a=0,,and then set (2-a) =0,,,to solve for a
Well, let a = "log x",, and repeat the exercise.
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log x(2-log x) = 0
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log x = 0,,,,,x=1
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2-log x =0,,,2= log x,,,,x=100
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check,,,(x=1),,,log1^2 =(log1)^2,,0=0,,,ok
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(x=100) log100^2 = (log100)^2,,,,4=4,,,,ok
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