SOLUTION: 5x+2y+7=0 solve for Y

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Question 203387This question is from textbook begining algebra
: 5x+2y+7=0 solve for Y This question is from textbook begining algebra

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
your equation is:
5x + 2y + 7 = 0
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if you subtract 7 from both sides of this equation, you get:
5x + 2y = 0 - 7
which is the same as:
5x + 2y = -7
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if you subtract 5x from both sides of this equation, you get:
2y = -7 - 5x
which is the same as:
2y = -5x - 7
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if you divide both sides of this equation by 2, you get:
y = (-5x - 7)/2
which looks like this:
y+=+%28-5x-7%29%2F2
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you just solved for y.
to prove your equation is good, take any value of x at random and solve for y and then substitute both values of x and y in the original equation.
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take x = 13
your equation is:
y = (-5x - 7)/2
which becomes:
y = (-5*(13) - 7)/2
which becomes:
y = (-65 - 7)/2
which becomes:
y = -72/2
which becomes:
y = -36
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you have:
x = 13
y = -36
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substitute in the original equation of:
5x + 2y + 7 = 0
which becomes:
5*13 + 2*(-36) + 7 = 0
which becomes:
65 - 72 + 7 = 0
which becomes:
-7 + 7 = 0
which becomes:
0 = 0
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since the equation is true after you substituted your chosen value of x and your calculated value of y, then your equation of y = (-5x - 7)/2 is good, and your answer is:
y = (-5x - 7)/2
which looks like:
y+=+%28-5x+-+7%29%2F2