SOLUTION: Rational expressions with different denominators
2x/x^2-9+3x/x^2+4x+3
I am confused on how to find a common denominator. I know for the first one it could be either 3x(x-3) o
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2x/x^2-9+3x/x^2+4x+3
I am confused on how to find a common denominator. I know for the first one it could be either 3x(x-3) o
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Question 203367This question is from textbook
: Rational expressions with different denominators
2x/x^2-9+3x/x^2+4x+3
I am confused on how to find a common denominator. I know for the first one it could be either 3x(x-3) or (x-3)(x+3) for the second denominator i can only think of (x+3)(x+1) i just don't know which denominator is missing what.
I apprecate any help you can give me thank you This question is from textbook
You can put this solution on YOUR website! Rational expressions with different denominators
2x/x^2-9 + 3x/x^2+4x+3
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You have to factor whereever you can so you can see the lcd:
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(2x)/[(x-3)(x+3)] + (3x)/[(x+3)(x+1)]
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The lcd must contain each unique factor it its hghest power.
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lcd = (x+1)(x+3)(x-3)
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Write each fraction over the lcd:
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[(2x)(x+1)]/lcd + [(3x)(x+3)]/lcd
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Combine the numerators over the lcd:
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[2x^2 + 2x + 3x^2+ 9x]/lcd
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Simplify:
[5x^2 + 11x]/ [(x+1)(x+3)(x-3)]
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Cheers,
Stan H.
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