Question 203304: Please I need help with word problem!
In 1994, the life expectancy of males in a certain country was 61.5 years. In 2001, it was 65.1 years. Let E represent the life expectancy in year t and let t represent the number of years since 1994.
The liner function E(t) that fits the date is
E(t)=? +?
Use th e function to predict the life expectancy of males in 2009.
E(15)=?
First point (0, 65.1)
Second point (7, 65.1)
M= 65.1-65.1
------------------
0-7
E(t)=0.7-65.1
E(15)=0.5(t)+65.1
E(15)=72.6
Thank you!
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In 1994, the life expectancy of males in a certain country was 61.5 years. In 2001, it was 65.1 years. Let E represent the life expectancy in year t and let t represent the number of years since 1994.
The linear function E(t) that fits the date is
E(t)=? +?
Use the function to predict the life expectancy of males in 2009.
E(15)=?
First point (0, 61.5)
Second point (7, 65.1)
M= (61.5-65.1)/(0-7) = -3.6/-7 = 0.5143
E-intercept = 61.5
E(t) = 0.5143t + 61.5
------------------
E(15)=0.5143(t)+61.5
E(15)=69.2142
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Cheers,
Stan H.
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