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| Question 203301:  find three consecutive odd integers such that the sum of the smallest and 7 times the largest is 68
 Answer by RAY100(1637)
      (Show Source): 
You can put this solution on YOUR website! Let  x =  1st  odd integer,,(x+2) =  2nd,,,,(x+4) = 3rd .
 (x) +7*(x+4) =68
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 x + 7x +28 =68
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 8x =40
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 x=5,,,ist  integer,,,7=next,,,,,9=last
 .
 check, 5 +7*9 = 5 + 63 =68,,,ok
 
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