SOLUTION: A rocket is launched from atop a 92 foot cliff with an initial vertical velocity of 112 feet per second. The height of the rocket t seconds after launch is given by the equation h=

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Question 203282: A rocket is launched from atop a 92 foot cliff with an initial vertical velocity of 112 feet per second. The height of the rocket t seconds after launch is given by the equation h= -16t^2+112t+92. Graph the equation to find out how long after the rocket is launched it will hit the ground. Estimate your answer to the nearest tenth of a second.
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Graph:
h%28t%29+=+-16t%5E2%2B112t%2B92
graph%28400%2C400%2C-5%2C10%2C-5%2C290%2C-16x%5E2%2B112x%2B92%29
When h (vertical axis) = 0, t = 7.75 approximately.
So the rocket will hit the ground (h = 0) in about 7.75 seconds after launch.