SOLUTION: One pump can fill a tank twice as fast as a second pump. If the pumps are used together, they fill the tank in 16 minutes. How long would it take each pump working alone to fill th

Algebra ->  Rate-of-work-word-problems -> SOLUTION: One pump can fill a tank twice as fast as a second pump. If the pumps are used together, they fill the tank in 16 minutes. How long would it take each pump working alone to fill th      Log On


   



Question 203145: One pump can fill a tank twice as fast as a second pump. If the pumps are used together, they fill the tank in 16 minutes. How long would it take each pump working alone to fill the tank?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
One pump can fill a tank twice as fast as a second pump. If the pumps are used together, they fill the tank in 16 minutes. How long would it take each pump working alone to fill the tank?
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Faster pipe DATA:
time = x min/job ; rate = 1/x job/min
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Slower pipe DATA:
time = 2x min/job ; rate = 1/(2x) job/min
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Together DATA:
time = 16 min/job ; rate = 1/16 job/min
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Equation:
rate + rate = together rate
1/x + 1/(2x) = 1/16
Multiply thru by 16x to get:
16 + 8 = x
x = 24 minutes (time for the faster pipe to do the job)
2x = 48 minutes (time for the slower pipe to do the job)
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Cheers,
Stan H.