SOLUTION: f(x)=In ((x^2+4)/3X)) partheness around the whole equation compute f'(x) then find the exact value of f'(6) f'(6)= not sure what to do can someone help thanks

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: f(x)=In ((x^2+4)/3X)) partheness around the whole equation compute f'(x) then find the exact value of f'(6) f'(6)= not sure what to do can someone help thanks      Log On


   

Question 202978: f(x)=In ((x^2+4)/3X)) partheness around the whole equation
compute f'(x) then find the exact value of f'(6)
f'(6)=
not sure what to do
can someone help
thanks
Found 2 solutions by rfer, stanbon:
Answer by rfer(16322) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=(x^2+4)/3x
f(x)=y=(6^2+4)/3(6)
y=(36+4)/18
y=40/18
y=2.22

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=In ((x^2+4)/3X)) partheness around the whole equation
compute f'(x)
f'(x) = (3x/(x^2+4))[(3x)(2x)-(x^2+4)(3)]/[(3x)^2
---------------------------------------------------------
Then find the exact value of f'(6)
f'(6)=(18)/(40)[(18)(12) - (40)(3)]/(18)^2
etc.
Cheers,
Stan H.