You can put this solution on YOUR website! There are several properties of logarithms which are useful when you want to manipulate expressions involving them:
Used from left to right, this property can be used to separate factors in the argument of a logarithm into separate logarithms. Used from right to left this can be used to combine the sum of two logarithms into a single, equivalent logarithm.
Used from left to right, this property can be used to separate the numerator and denominator of a fraction in the argument of a logarithm into separate logarithms. Used from right to left this can be used to combine the difference of two logarithms into a single, equivalent logarithm.
Used from left to right, this property can be used to "move" of the argument of a logarithm out in front of the logarithm (as a coefficient. Used from right to left this can be used to "move" a coefficient of a logarithm into the arguments as the exponent of the logarithm.
This property is used most used from left to right in order to change the base of a logarithm from "a" to "b".
We will use these properties to simplify
(If the above is not a correct representation of your problem, please repost the question using more parentheses to clarify "what goes with what and where".)
The argument of the first log is a fraction and we will use property #2 above to separate the numerator and denominator into separate logs: .
And square roots are the same as an exponent of (1/2). Using these facts to rewrite our expression we get:
Now we can use property #3 above to "move" the exponents out from the arguments to the front of the 2ns and 3rd logs:
Now we can use property #1 above to separate the "a" and the "x" in the third log into separate logs. (Note the parentheses used when substituting. They are critical.)
Again .
Simplifying we get:
Combining like terms (1 - (1/2) = 1/2; -1/2log - 1/2log = -1log):