SOLUTION: I would appreciate it if someone could tell me if these are right. Thanks so much Express in simplest radical form. sqrt 25a^2b^2 I get 5ab^2 = sqrt25 x sqrta^2 x sqrt b^2 = 5

Algebra ->  Square-cubic-other-roots -> SOLUTION: I would appreciate it if someone could tell me if these are right. Thanks so much Express in simplest radical form. sqrt 25a^2b^2 I get 5ab^2 = sqrt25 x sqrta^2 x sqrt b^2 = 5       Log On


   

Question 202919This question is from textbook
: I would appreciate it if someone could tell me if these are right. Thanks so much
Express in simplest radical form.
sqrt 25a^2b^2
I get 5ab^2 = sqrt25 x sqrta^2 x sqrt b^2 = 5 horizonal line ab horzonal line
sqrt 50x^2
I get sqrt50 x sqrt x^2 = 50 horizonal line x horzonal line or is this right
sqrt 25times2 = 25sqrt x 2sqrt = 5sqrt2
6sqrt7 x 3 sqrt5
I get (6 x 3) (sqrt& x sqrt5) = 18 sqrt35
3sqrt2 + sqrt50
I get 3(sqrt52) or do I have to simplify the sqrt50 down further
 This question is from textbook

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
1. sqrt%2825a%5E2b%5E2%29+=+highlight%285ab%29
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2. sqrt%2850x%5E2%29+=+sqrt%2850%29%2Asqrt%28x%5E2%29=sqrt%282%2A25%29%2Ax+=+highlight%285%2Asqrt%282%29%2Ax%29
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3. 6sqrt%287%29%2A3sqrt%285%29+=+18%2Asqrt%287%2A5%29=highlight%2818sqrt%2835%29%29
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4. 3sqrt%282%29%2Bsqrt%2850%29+=+3sqrt%282%29%2Bsqrt%282%2A25%29=3sqrt%282%29%2B5sqrt%282%29+=+highlight%288sqrt%282%29%29