SOLUTION: 2 times the square root of x minus 1 minus the square root of 3x minus 5 equals the square root of x minus 9
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-> SOLUTION: 2 times the square root of x minus 1 minus the square root of 3x minus 5 equals the square root of x minus 9
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Algebra: Radicals -- complicated equations involving roots
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Question 202564
:
2 times the square root of x minus 1 minus the square root of 3x minus 5 equals the square root of x minus 9
Answer by
jim_thompson5910(35256)
(
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):
You can
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Start with the given equation.
Square both sides
Square the square root.
FOIL
Distribute
Combine like terms.
Get all the non-radical terms to one side
Combine like terms.
Combine the roots.
Divide both sides by -4.
Reduce
Square both sides
Square the square root
Square the right side
Multiply both sides by 4.
FOIL
Distribute
Subtract {{9x^2}}} from both sides.
Combine like terms.
Notice that the quadratic
is in the form of
where
,
, and
Let's use the quadratic formula to solve for "x":
Start with the quadratic formula
Plug in
,
, and
Negate
to get
.
Square
to get
.
Multiply
to get
Subtract
from
to get
Multiply
and
to get
.
Take the square root of
to get
.
or
Break up the expression.
or
Combine like terms.
or
Simplify.
So the
possible
solutions are
or
However, if you plug in
into the original equation, you'll get a contradiction.
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Answer:
So the only solution is