SOLUTION: Drawing a heart and a diamond in any order in 2 consecutive draws, when the 1st card is not returned to the deck after the 1st draw. My Answer: 26/52+13/51=1326/2652+676/2652=2

Algebra ->  Probability-and-statistics -> SOLUTION: Drawing a heart and a diamond in any order in 2 consecutive draws, when the 1st card is not returned to the deck after the 1st draw. My Answer: 26/52+13/51=1326/2652+676/2652=2      Log On


   

Question 202521: Drawing a heart and a diamond in any order in 2 consecutive draws, when the 1st card is not returned to the deck after the 1st draw.
My Answer: 26/52+13/51=1326/2652+676/2652=2002/2652=1001/1326
Found 2 solutions by rfer, jim_thompson5910:
Answer by rfer(16322) About Me  (Show Source):
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Note: with "and", you multiply the probabilities


P(heart AND diamond) = P(heart) * P(diamond)


P(heart AND diamond) = (13/52) * (13/51)


P(heart AND diamond) = 169/2652


P(heart AND diamond) = 13/204