SOLUTION: I need to know how to set this problem up....
A silversmith combined pure silver that cost $5.20 per ounce with 50 oz of a silver alloy that cost $ 2.80 per ounce. How many ounc
Algebra ->
Expressions-with-variables
-> SOLUTION: I need to know how to set this problem up....
A silversmith combined pure silver that cost $5.20 per ounce with 50 oz of a silver alloy that cost $ 2.80 per ounce. How many ounc
Log On
Question 202462: I need to know how to set this problem up....
A silversmith combined pure silver that cost $5.20 per ounce with 50 oz of a silver alloy that cost $ 2.80 per ounce. How many ounces of the pure silver were used to make an alloy of silver costing $4.40 per ounce? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! I need to know how to set this problem up....
A silversmith combined pure silver that cost $5.20 per ounce with 50 oz of a
silver alloy that cost $ 2.80 per ounce. How many ounces of the pure silver
were used to make an alloy of silver costing $4.40 per ounce?
:
Treat it like a typical mixture problem
Let x = amt of pure silver required ($5.20)
Since the resulting total is 50 oz,
(50-x) = amt of $2.80 silver required
:
5.2x + 2.8(50-x) = 4.4(50)
:
Solve for x