SOLUTION: An Air Force plane flew to Jakarta and back. It took six hours longer to go there than it did to come back. The average speed on the trip there was 182 km/h. The average speed o

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Question 202389: An Air Force plane flew to Jakarta and back. It took six hours longer to go there than it did to come back. The average speed on the trip there was 182 km/h. The average speed on the way back was 455 km/h. How many hours did the trip there take?
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Using the distance formula:
d+=+rt where: d = distance, r = rate (speed), and t = time of travel.
For the trip to Jakarta:
d%5B1%5D+=+r%5B1%5D%2At%5B1%5D Substitute: r%5B1%5D+=+182 and t%5B1%5D+=+t%5B2%5D%2B6
d%5B1%5D+=+%28182%29%28t%5B2%5D%2B6%29
For the return trip:
d%5B2%5D+=+r%5B2%5D%2At%5B2%5D Substitute: r%5B2%5D+=+455
d%5B2%5D+=+455%2At%5B2%5D
The distance to Jakarta is equal to the return distance, so...
d%5B1%5D+=+d%5B2%5D and so...
%28182%29%28t%5B2%5D%2B6%29+=+455%2At%5B2%5D Simplify and solve for t%5B2%5D
182%2At%5B2%5D%2B1092+=+455%2At%5B2%5D Subtract 182%2At%5B2%5D from both sides of the equation.
1092+=+273%2At%5B2%5D Divide both sides by 273.
t%5B2%5D+=+4hours.
t%5B1%5D+=+t%5B2%5D%2B6
t%5B1%5D+=+4%2B6
highlight%28t%5B1%5D+=+10%29hours.
Check:
10%2A182+=+4%2A455
1820+=+1820 OK!