SOLUTION: My problem is: 5> (x-3)/4 > 1 I tried 4x5 > 4(x-3)/4 > 1x4 20 > x-3 > 4 +3 > +3 > +3 23 > x > 7 This does not look correct. Can you show me where I went wrong in this

Algebra ->  Graphs -> SOLUTION: My problem is: 5> (x-3)/4 > 1 I tried 4x5 > 4(x-3)/4 > 1x4 20 > x-3 > 4 +3 > +3 > +3 23 > x > 7 This does not look correct. Can you show me where I went wrong in this       Log On


   



Question 20238: My problem is:
5> (x-3)/4 > 1
I tried
4x5 > 4(x-3)/4 > 1x4
20 > x-3 > 4
+3 > +3 > +3
23 > x > 7
This does not look correct. Can you show me where I went wrong in this equation?
Thanks

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Well, I don't see anything wrong with what you have done.
You might ask yourself..."Why do I think it doesn't look correct?"
Try graphing the result on a number line to convince yourself that you have done it correctly and have the right answer.
Alternatively, you could try some integers in the range: 23%3E+x+%3E+7
and see that they work.
And try some outside the range.
Example:
Try x = 15 (within the range)
5+%3E+%2815-3%29%2F4+%3E+1
5+%3E+12%2F4+%3E+1
5+%3E+3+%3E+1 This is true!
Example:
Try x = 27 (outside the range)
5+%3E+%2827-3%29%2F4+%3E+1
5+%3E+24%2F4+%3E+1
5+%3E+6+%3E+1 Remember, both conditions must be true for the statement to be true, so this is false!