SOLUTION: The standard form of a circle whose center is (-3,2) and radius 4 is (1)(x-3)^2+(y+2)^2=16 (2)(x+3)^2+(y-2)^2=16 (3) (x-3)^2+(y+2)^2=4 (4) (x+3)^2+(y-2)^2=4

Algebra ->  Graphs -> SOLUTION: The standard form of a circle whose center is (-3,2) and radius 4 is (1)(x-3)^2+(y+2)^2=16 (2)(x+3)^2+(y-2)^2=16 (3) (x-3)^2+(y+2)^2=4 (4) (x+3)^2+(y-2)^2=4      Log On


   

Question 202358: The standard form of a circle whose center is (-3,2) and radius 4 is (1)(x-3)^2+(y+2)^2=16 (2)(x+3)^2+(y-2)^2=16 (3) (x-3)^2+(y+2)^2=4 (4) (x+3)^2+(y-2)^2=4
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
standard for for a circle is,,,,(x-h)^2 +(y-k)^2 = r^2
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center is (h,k),, in this case (-3,2),,,or h=(-3),,k=(2)
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r=4,,,,r^2 =16
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{ x-(-3)}^2 + {y-(2)}^2 = {4}^2
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(x+3)^2 +(y-2)^2 =16
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this matches,,,( 2 ) above