SOLUTION: 5b^2 *(4b^2-3b) --------- 40b^3-30b^2

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 5b^2 *(4b^2-3b) --------- 40b^3-30b^2      Log On


   

Question 202348: 5b^2 *(4b^2-3b)
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40b^3-30b^2
Answer by PRMath(133) About Me  (Show Source):
You can put this solution on YOUR website!
I answered this already today so I will copy and paste that answer here. I hope you find it this time! :-)
I think this is your problem:
5b%5E2%284b%5E2-3b%29/40b%5E3-30b%5E2

There's probably a way to make that fraction look better but I've tried a few times and I haven't mastered it. Clearly, I need a tutor for how to make math problems look good on this website.

Anyway, if the above is your problem, here is what you do.....


Let's first focus on your denominator:

40b%5E3-30b%5E2 Is there a number or variable (or both) that is common to both? How about 10b? Do you see how 10b is in 40b%5E3 as well as 30b%5E2?

SO let's factor out that 10b......

40b%5E3-30b%5E2 = 10b%284b%5E2+-+3b%29


So now your new problem (with the revised denominator is)....

5b%5E2%284b%5E2-3b%29/10b%284b%5E2+-+3b%29



Now can you see that the 4b%5E2-3b%29 in the numerator will factor out the 4b%5E2-3b%29 in the denominator??

SO, now you have:

5b%5E2%2F10b and this can be reduced to

1b%5E2%2F2b and (you are STILL not done!) this can be reduced to

1b%2F2

I hope this helps you. :-)