SOLUTION: find (a)the directrix, (b)the focus, and (c)the roots of the parabola y = x^2 - 5x + 4

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Question 202316: find (a)the directrix, (b)the focus, and (c)the roots of the parabola
y = x^2 - 5x + 4

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
find (a)the directrix, (b)the focus, and (c)the roots of the parabola
y+=+x%5E2+-+5x+%2B+4


We have to get it in the form 

%28x-h%29%5E2=4p%28y-k%29


y+=+x%5E2+-+5x+%2B+4

Swap sides:

x%5E2+-+5x+%2B+4+=+y

Add -4 to both sides the get the x-terms alone on the left.

x%5E2+-+5x=y-4

Multiply the coefficient of x, which is -5 by 1%2F2
This gives -5%2F2.  Now we square -5%2F2 and get %22%22%2B25%2F4
We add %22%22%2B25%2F4 to both sides:

x%5E2+-+5x%2B25%2F4=y-4%2B25%2F4

Factor the left side, and write the -4 as -16%2F4

%28x-5%2F2%29%28x-5%2F2%29=y-16%2F4%2B25%2F4

Write the left side as the square of a binomial,
combine the fractions on the right:

%28x-5%2F2%29%5E2=y%2B9%2F4

Now so that equation will look like this:

%28x-h%29%5E2=4p%28y-k%29

we put the right side in parentheses and put a 1
coefficient before the parentheses, like this:

%28x-5%2F2%29%5E2=1%28y%2B9%2F4%29

Now we can compare it to the equation:

%28x-h%29%5E2=4p%28y-k%29

and get -h=-5%2F2, so h=5%2F2

-k=%22%22%2B9%2F4, so k=-9%2F4

So the vertex is (h,k) or (5%2F2,-9%2F4)

And 4p=1, so p=1%2F4

Now let's begin by plotting the vertex, which is (5%2F2,3%2F2),

But for plotting purposes, mixed numbers are better
than improper fractions, so for plotting vertex (5%2F2,-9%2F4),
we rewrite it as (2%261%2F2,-2%261%2F4)




Now we will find the x-intercepts, by settng y=0
in the original equation, and finding the "roots":

y+=+x%5E2+-+5x+%2B+4
0+=+x%5E2+-+5x+%2B+4
0+=+%28x-1%29%28x-4%29
x-1=0, so x=1
x-4=0, so x=4

So the x-intecepts are (1,0) and (4,0) 

So we plot those:



and sketch in the parabola:



Now the focus is p units from the vertex INSIDE
the parabola, so since the parabola opens upward,
we add P or 1%2F4 to the y-coordinate of the
vertex. Since the vertx is (5%2F2,-9%2F4),
the focus = (5%2F2,-9%2F4%2B1%2F4) = (5%2F2,-8%2F4) 
= (5%2F2,-2)

So we draw that point:



Now the directrix is a line OUTSIDE the parabola which is
also p-units, or 1%2F4 from the vertex.

Since the y-coordinate of the vertex is -9%2F4 we want
the directrix to be 1%2F4 unit below the vertex, so we
subtract -9%2F4-1%2F4=-10%2F4=-5%2F2

So the directrix is the horizontal line whose equation is 

y=-5%2F2.  I'll draw it in in green:



So the focus is the POINT (5%2F2,-2) and the 

directrix is the LINE y=-5%2F2

The "roots" are really the y-coordinates of the 
x-intercepts or 1 and 4.

Edwin