Question 202095: Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less than the square of the largest number Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! x, x+2, x+4 are the 3 even numbers.
x(x+2)+64=(x+4)^2
x^2+2x+64=x^2+8x+16
2x-8x=-64+16
-6x=-48
x=-48/-6
x=8 ans. for the smaller number
8+2=10 for the middle number
8+4=12 for the larger number
Proof:
8(10)+64=12^2
80+64=144
144=144