Question 202091:
Answer by PRMath(133)   (Show Source):
You can put this solution on YOUR website! Simplify these following expressions:
(2x)^4 x^3
(-3y)^4
(3z)^2(6z^2)^-3
5x2⁄25x5
10(x+y)^4/5(x+y)^3
1/6x(3x^2)^3
(5x^2)^3(1/25x^4)^2
(2z^2)^-5*z^-10
(3/x)^4(4/x)^-2
[2(r-s)]^2/(r-s)^3
Let's take a few at a time......
I see your first problem as this:
 *
If that is the problem, then you multiply:
2 to the 4th power -- 2*2*2*2 = 16 (You distribute the exponent "4" to the 2 and to the "x"....
and then you multiply  * . Since the bases are the same, you ADD the exponents, so you have 
FINAL answer: 
Next:(-3y)^4
That is: -3*-3*-3*-3 = 81 (See how the exponent 4 is distributed to the -3 and to the y?)
 is the second part of the answer
FINAL answer: 
Next: (3z)^2(6z^2)^-3
If the problem is this:  * raised to the power of -3
That is  times  times 
That becomes: * 
Why? The exponent "2" distributes to the 3 and to the z.
The exponent -3 distributes to the 6 and to the "z". HOWEVER, for the "z", because you are raising a power to a power, you have to MULTIPLY the exponents. Therefore, the "z" becomes or.... 
The problem is now:
/
THAT becomes
 (we reduced the fraction  to  .
Let's stop here for a second and go over some exponent rules, k? Then if you need help with your other answers, ask again. It seems like you may not understand exponents...........
 * =  When multiplying... if the bases are the same, ADD the exponents
/ =  When dividing... if the bases are the same, SUBTRACT the exponents
If you raise a power to a power, then MULTIPLY the exponents.
If you have a NEGATIVE exponent in the NUMERATOR, just put it in the denominator and make it a POSITIVE exponent:
 is really: 
If you have a NEGATIVE EXPONENT in the DENOMINATOR, just put it in the numerator and make it a POSITIVE exponent.
 is really:
I hope this helps......
| |
|
