SOLUTION: Find the domain of f(x)=sqrt x-4. thanks

Algebra ->  Coordinate-system -> SOLUTION: Find the domain of f(x)=sqrt x-4. thanks       Log On


   



Question 202032: Find the domain of f(x)=sqrt x-4. thanks




Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%28x-4%29 Start with the given expression

Remember you cannot take the square root of a negative value. So that means the argument x-4 must be greater than or equal to zero (i.e. the argument must be non-negative)

x-4%3E=0 Set the inner expression greater than or equal to zero

x%3E=0%2B4Add 4 to both sides


x%3E=4 Combine like terms on the right side


So that means x must be greater than or equal to 4 in order for x to be in the domain

So the domain in set-builder notation is


So here is the domain in interval notation: [4,)



Notice if we graph y=sqrt%28x-4%29 , we get
+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+sqrt%28x-4%29%29+ notice how the graph never crosses the line x=4. So this graphically verifies our answer.

and we can see that x must be greater than or equal to 4 in order to lie on the graph