SOLUTION: 64^x=4 please help if you do not mind. thank you very much

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 64^x=4 please help if you do not mind. thank you very much      Log On


   

Question 20202: 64^x=4
please help if you do not mind. thank you very much
Found 2 solutions by Earlsdon, dylansaunders:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You can solve for x by taking the logarithm of both sides of the equation and solving for x.
log%2864%5Ex%29+=+log%284%29
xlog64+=+log%284%29 Divide both sides by log64
x+=+log4%2Flog64
x+=+log4%2Flog4%5E3
x+=+log4%2F3log4
x+=+1%2F3
Check:
64%5E%281%2F3%29+=+4

Answer by dylansaunders(2) About Me  (Show Source):
You can put this solution on YOUR website!
64^x=4
log64^x=log4
xlog64=log4
Then you divide by: xlog64/log64= log4/log64
Then you divide them and you get: .3333