SOLUTION: 3x+3y+z=8 x-3y+2z=-3 8x-2y+3z=11

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Question 202000: 3x+3y+z=8
x-3y+2z=-3
8x-2y+3z=11
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solution provided by the Linear Algebra Toolkit





So the ordered triple solution is (2, 1, -1) which means that x=2, y=1, and z=-1