SOLUTION: Help Needed; Graph the feasible region for the system of inequalities. 3x - 2y ≤ 6 x - y ≥ 0

Algebra ->  Graphs -> SOLUTION: Help Needed; Graph the feasible region for the system of inequalities. 3x - 2y ≤ 6 x - y ≥ 0       Log On


   



Question 201962: Help Needed;
Graph the feasible region for the system of inequalities.
3x - 2y ≤ 6
x - y ≥ 0

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Start with the given system of inequalities
3x-2y%3C=6
x-y%3E=0

In order to graph this system of inequalities, we need to graph each inequality one at a time.


First lets graph the first inequality 3x-2y%3C=6
In order to graph 3x-2y%3C=6, we need to graph the equation 3x-2y=6 (just replace the inequality sign with an equal sign).
So lets graph the line 3x-2y=6 (note: if you need help with graphing, check out this solver)
+graph%28+500%2C+500%2C+-20%2C+20%2C+-20%2C+20%2C+%283%2F2%29x-3%29+ graph of 3x-2y=6
Now lets pick a test point, say (0,0). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality 3x-2y%3C=6 with the test point

Substitute (0,0) into the inequality
3%280%29-2%280%29%3C=6 Plug in x=0 and y=0
0%3C=6 Simplify



(note: for some reason, some of the following images do not display correctly in Internet Explorer. So I recommend the use of
Firefox to see these images.)


Since this inequality is true, we simply shade the entire region that contains (0,0)
Graph of 3x-2y%3C=6 with the boundary (which is the line 3x-2y=6 in red) and the shaded region (in green)

---------------------------------------------------------------


Now lets graph the second inequality x-y%3E=0
In order to graph x-y%3E=0, we need to graph the equation x-y=0 (just replace the inequality sign with an equal sign).
So lets graph the line x-y=0 (note: if you need help with graphing, check out this solver)
+graph%28+500%2C+500%2C+-20%2C+20%2C+-20%2C+20%2C+x%29+ graph of x-y=0
Now lets pick a test point, say (0,1). Any point will work, (just make sure the point doesn't lie on the line) but this point is the easiest to work with. Now evaluate the inequality x-y%3E=0 with the test point

Substitute (0,1) into the inequality
%280%29-%281%29%3E=0 Plug in x=0 and y=1
1%3E=0 Simplify



Since this inequality is true, we simply shade the entire region that contains (0,1)
Graph of x-y%3E=0 with the boundary (which is the line x-y=0 in red) and the shaded region (in green)

---------------------------------------------------------------


So we essentially have these 2 regions:

Region #1
Graph of 3x-2y%3C=6


Region #2
Graph of x-y%3E=0




When these inequalities are graphed on the same coordinate system, the regions overlap to produce this region. It's a little hard to see, but after evenly shading each region, the intersecting region will be the most shaded in.







Here is a cleaner look at the intersection of regions




Here is the intersection of the 2 regions represented by the series of dots