SOLUTION: Throwing a wrench: An angry contruction worker throws his wrench downward from a height of 128 ft with an initial velocity of 32 feet per second. The height of the wrench above th
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Question 201852: Throwing a wrench: An angry contruction worker throws his wrench downward from a height of 128 ft with an initial velocity of 32 feet per second. The height of the wrench above the ground after t seconds is given by
S(t) = -16r - 32r + 128
A. What is the height of the wrench after 1 second?
B. How long does it take for the wrench to reach the ground? Found 2 solutions by Alan3354, Earlsdon:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! An angry contruction worker throws his wrench downward from a height of 128 ft with an initial velocity of 32 feet per second. The height of the wrench above the ground after t seconds is given by
S(t) = -16r - 32r + 128
A. What is the height of the wrench after 1 second?
B. How long does it take for the wrench to reach the ground?
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You have r's in a function that's S(t) ??
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h(t) = -16t^2 -32t + 128
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A. h(1) = -16 - 32 + 128
h(1) = 80 feet
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B. -16t^2 - 32t + 128 = 0
t^2 + 2t - 8 = 0
(t+4)*(t-2) = 0
t = 2 seconds to reach the ground
You can put this solution on YOUR website! First, it appears as though that you have a little mix-up in the independent variable (t) in the formula. It should be:
A) What is the height of the wrench after 1 second?
Set t = 1 and solve for S. feet.
B) How long does it take for the wrench to reach the ground?
Here, you are looking for the time, t, at which S(t) is zero (ground-level), so set S(t) = 0 and solve for t. To simplify the calculations a bit, divide both sides by -16. Factor the trinomial. Now apply the zero product rule. or so then... or Discard the negative solution as time is a positive value. seconds.