SOLUTION: Jeb has 25 coins.They are all quarters and nickels. He has a total of $2.85. How many quarters and nickels does he have? construct an algebraic equation, solve the variable, and an
Question 201797: Jeb has 25 coins.They are all quarters and nickels. He has a total of $2.85. How many quarters and nickels does he have? construct an algebraic equation, solve the variable, and answer the question. You must solve the problem using algebra Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Jeb has 25 coins.They are all quarters and nickels. He has a total of $2.85. How many quarters and nickels does he have?
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n + q = 25 --> q = 25-n
5n + 25q = 285
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Sub for q in 2nd eqn
5n + 25(25-n) = 285
n + 5(25-n) = 57
n + 125 - 5n = 57
-4n = -68
n = 17 nickels
q = 8 quarters