SOLUTION: FIND THE VALUE OF 'X' BY QUADRATIC FORMULA 1. 9x^2-9(a+b)x+2a^2+5ab+2ab^2=0 2.a^2b^2x-(4b^4-3a^4)x-12a^2b^2=0 I WILL BE THANKFUL PRIYAL

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: FIND THE VALUE OF 'X' BY QUADRATIC FORMULA 1. 9x^2-9(a+b)x+2a^2+5ab+2ab^2=0 2.a^2b^2x-(4b^4-3a^4)x-12a^2b^2=0 I WILL BE THANKFUL PRIYAL      Log On


   

Question 201666: FIND THE VALUE OF 'X' BY QUADRATIC FORMULA
1. 9x^2-9(a+b)x+2a^2+5ab+2ab^2=0
2.a^2b^2x-(4b^4-3a^4)x-12a^2b^2=0
I WILL BE THANKFUL
PRIYAL
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Simply use the quadratic formula x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29+ to solve any equation of the form Ax%5E2%2BBx%2BC=0. So for instance, the first equation 9x%5E2-9%28a%2Bb%29x%2B2a%5E2%2B5ab%2B2ab%5E2=0 yields the values A=9, B=-9%28a%2Bb%29 and C=2a%5E2%2B5ab%2B2ab%5E2. Simply plug these values into the quadratic formula to solve for "x". Do the same for the second problem.