SOLUTION: Sorry I submitted my problem wrong, the question is ln(4x)=ln(x+5) can you help with this problem, please?

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Question 201583: Sorry I submitted my problem wrong, the question is ln(4x)=ln(x+5) can you help with this problem, please?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Since the bases of the logs are equal (they are both base "e"), this means that the arguments (the stuff inside) MUST be equal. So...


4x=x%2B5 Set the arguments equal to one another.


4x-x=5 Subtract x from both sides.


3x=5 Combine like terms on the left side.


x=%285%29%2F%283%29 Divide both sides by 3 to isolate x.


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Answer:

So the solution is x=5%2F3 which approximates to x=1.667.