Consider a standard deck of playing cards (52 cards, no jokers). If you draw one card, what is the probability that the card is:
a. a spade?
There are 13 spades out of 52 cards, so we put 13 over 52 and reduce:
b. a seven (7)?
There are 4 7's out of 52 cards, so we put 4 over 52 and reduce:
c. a seven (7) and a spade?
There is just one car that is both a 7 and a spade and
that is the 1 card the 7 of spades. So we put 1 over 52:
d. a seven (7) or a spade?
Now we use the formula
P(A OR B) = P(A) + P(B) - P(A AND B)
P(7 OR Spade) = P(7) + P(Spade) - P(7 AND Spade)
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Edwin