SOLUTION: A father is 8 times as old as his son and 4 times as old as his daughter. If the daughter is 5 years older than the son;how old is each?
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Question 201311: A father is 8 times as old as his son and 4 times as old as his daughter. If the daughter is 5 years older than the son;how old is each? Answer by ptaylor(2198) (Show Source):
You can put this solution on YOUR website! Let x=son's age
Then x+5=daughter's age
8x=father's age
Also 4(x+5)=father's age, so:
8x=4(x+5) get rid of parens
8x=4x+20 subtract 4x from each side
8x-4x=4x-4x+20
4x=20 divide each side by 4
x=5--------------son's age
x+5=5+5=10 daughter's age
8x=8*5=40-----------father's age
CK
8*5=4(5+5)
40=40