Question 201169This question is from textbook intermediate algebra an applied approach
: Pg 505
42. Find the x-intercepts of the parabola given by each equation.
y=x^2+6x+10
This question is from textbook intermediate algebra an applied approach
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! y = x^2 +6x+10
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To find x intercepts, set y=0,,and solve eqn
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x^2 +6x+10 =0
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Using quadratic eqn to factor
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a=1,,,b=6,,,c=10
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x=[ -(6) +/- sqrt (6^2 -4(1)(10)] /2 (1)
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x=[-6 +/- sqrt (-4) ] /2
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x= -3 +/- 2i,,,,,,,or no real number intercepts
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further review shows an upward pointing y parabola,,,with vertex at (-3,1)
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