SOLUTION: find the radius of a circle: x^2+y^2-12x+8y+43=0

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Question 201163: find the radius of a circle:
x^2+y^2-12x+8y+43=0

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Find the radius of the circle:
x%5E2%2By%5E2-12x%2B8y%2B43+=+0
To do this, you need to change the given equation into the general form for a circle with center at (h, k) and radius, r,: %28x-h%29%5E2%2B%28y-k%29%5E2+=+r%5E2.
You can do this by using the method of "completing the square".
First, group the terms of the given equation as shown:
%28x%5E2-12x%29%2B%28y%5E2%2B8y%29%2B43+=+0 Next, subtract 43 from both sides of the equation.
%28x%5E2-12x%29%2B%28y%5E2%2B8y%29+=+-43 Now complete the square in the x-group and in the y-group by adding the square of half the x-coefficient and the square of half the y-coefficient to both sides of the equation.
Now factor the x-trinomial and the y-trinomial and simplify the right side of the equation.
%28x-6%29%5E2%2B%28y%2B4%29%5E2+=+9 Compare this result with the standard form given above:
%28x-h%29%5E2%2B%28y-k%29%5E2+=+r%5E2
You can see that the radius squared is r%5E2+=+9 so the radius must be highlight%28r+=+3%29 and, incidentally, you now have the center of the circle, (h, k) and it's (6,-4)