SOLUTION: The sum of the squares of two consecutive positive intergers is 164 find the intergers,and please include the heading to define the variables.

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Question 20110: The sum of the squares of two consecutive positive intergers is 164 find the intergers,and please include the heading to define the variables.
Found 2 solutions by wuwei96815, olayinka003:
Answer by wuwei96815(245) About Me  (Show Source):
You can put this solution on YOUR website!
n=the first positive integer
n+2=the second positive integer

n^2 + n^2+2 = 164
n^2 + n^2 = 164-2
2n^2 = 162
n^2 = 162/2 = 91
n = 9
n+2 = 11

I hope that you are satisfied with this solution.

Answer by olayinka003(5) About Me  (Show Source):
You can put this solution on YOUR website!
let x be the first positive integer
let y be the second positive integer
x^2 + n^2 + 2 = 164
x^2 + n^2 = 164 - 2
2n^2 = 162
n^2 = 162/2
n^2 = 81
squaring the both sides we have:
n = 9(first positive integer)
n^2 + 2 (second positive integer).
you ll see that n=9 and sqrt of 9 =81
n^2+ 2=81 + 2 =83
164
hope you got it