SOLUTION: Factor completely. x^3y + 4x^2y^2 - 21xy^3

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Question 201040: Factor completely.
x^3y + 4x^2y^2 - 21xy^3

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

x%5E3y%2B4x%5E2y%5E2-21xy%5E3 Start with the given expression


xy%28x%5E2%2B4xy-21y%5E2%29 Factor out the GCF xy


Now let's focus on the inner expression x%5E2%2B4xy-21y%5E2




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Looking at 1x%5E2%2B4xy-21y%5E2 we can see that the first term is 1x%5E2 and the last term is -21y%5E2 where the coefficients are 1 and -21 respectively.

Now multiply the first coefficient 1 and the last coefficient -21 to get -21. Now what two numbers multiply to -21 and add to the middle coefficient 4? Let's list all of the factors of -21:



Factors of -21:
1,3,7,21

-1,-3,-7,-21 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -21
(1)*(-21)
(3)*(-7)
(-1)*(21)
(-3)*(7)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4

First NumberSecond NumberSum
1-211+(-21)=-20
3-73+(-7)=-4
-121-1+21=20
-37-3+7=4



From this list we can see that -3 and 7 add up to 4 and multiply to -21


Now looking at the expression x%5E2%2B4xy-21y%5E2, replace 4xy with -3xy%2B7xy (notice -3xy%2B7xy adds up to 4xy. So it is equivalent to 4xy)

x%5E2%2Bhighlight%28-3xy%2B7xy%29-21y%5E2


Now let's factor x%5E2-3xy%2B7xy-21y%5E2 by grouping:


%28x%5E2-3xy%29%2B%287xy-21y%5E2%29 Group like terms


x%28x-3y%29%2B7y%28x-3y%29 Factor out the GCF of x out of the first group. Factor out the GCF of 7y out of the second group


%28x%2B7y%29%28x-3y%29 Since we have a common term of x-3y, we can combine like terms

So x%5E2-3xy%2B7xy-21y%5E2 factors to %28x%2B7y%29%28x-3y%29


So this also means that x%5E2%2B4xy-21y%5E2 factors to %28x%2B7y%29%28x-3y%29 (since x%5E2%2B4xy-21y%5E2 is equivalent to x%5E2-3xy%2B7xy-21y%5E2)



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So our expression goes from xy%28x%5E2%2B4xy-21y%5E2%29 and factors further to xy%28x%2B7y%29%28x-3y%29


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Answer:

So x%5E3y%2B4x%5E2y%5E2-21xy%5E3 completely factors to xy%28x%2B7y%29%28x-3y%29