Question 201029: What is the mamium value of the function y=-x^2+3?
Found 2 solutions by RAY100, solver91311:
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! y = -x^2 +3,,,,,or,,,,y-3 =(-1) (x-0)^2
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remember the std form is ,,,,,y-k = a (x-h)^2
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in this case vertex(h,k) is at (0,3)
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as the coeff "a" is negative, the parabola points down, and vertex is a maximum
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Answer by solver91311(24713)  (Show Source):
You can put this solution on YOUR website!
I don't know what a "mamim" [sic] value is. However, since the graph of this function is a parabola opening downward, it does have a maximum value. I'll go out on a limb and presume that is what you meant to ask.
You know the graph opens downward because the lead coefficient is negative, therefore the value of the function at the vertex of the parabola is the maximum value of the function.
For any function  , the  -coordinate of the vertex is found by calculating:
Then the maximum value of the function is found by substituting the -coordinate of the vertex for in the function and then calculating the value of  . Note that the value of  in your given function is zero because  .
By the way, just on the off chance that my opening remarks caused you to roll your eyes and say "WHAT-ever", think about this: The only way that we can communicate on this system is in writing using the English language. Therefore, all of the niceties of correct spelling, grammar, syntax, and punctuation, as well as the strict definition of mathematical vocabulary must be observed in order to ensure that communication is consistently effective. Besides, writing correctly is a polite gesture of respect to those of us who volunteer our time to help you. Inattention to such details sends just the opposite message.
John
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