SOLUTION: POWER FROM A WINDMILL. The power p that can be obtained from a windmill is directly proportionl to the cube of the wind speed s. (a) Write an equation that expresses this variati

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Question 200988This question is from textbook algebra and trigonometry
: POWER FROM A WINDMILL. The power p that can be obtained from a windmill is directly proportionl to the cube of the wind speed s.
(a) Write an equation that expresses this variation.
(b) Find the constant of proportionality for a windmill that produces 96 watts of power when the wind is lowing at 20 mi/h.
(c) How much power will this windmill produce if the wind speed increases to 30mi/h?
This question is from textbook algebra and trigonometry

Found 2 solutions by stanbon, jojo14344:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The power p that can be obtained from a windmill is directly proportionl to the cube of the wind speed s.
(a) Write an equation that expresses this variation.
p(s) = ks^3
----------------------------
(b) Find the constant of proportionality for a windmill that produces 96 watts of power when the wind is lowing at 20 mi/h.
96 = k*20^3
k = 96/20^3
k = 0.012
Therefore the equation is p(s) = 0.012s^3
-------------------------------------------------
(c) How much power will this windmill produce if the wind speed increases to 30mi/h?
P(30) = 0.012*30^3
P(30) = 324 watts
==========================
Cheers,
Stan H.

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!


The power p that can be obtained from a windmill is directly proportionl to the cube of the wind speed s.

a) P+=+%28k%29%28s%5E3%29

b) When P = 96 watts; s = 20mi/hr: k = ?

96=k%2820%5E3%29 ---> cross%2820%5E3%29k%2Fcross%2820%5E3%29=96%2F20%5E3=96%2F8000
red%28k=0.012%29

c) k = 0.012 ; s= 30 mi/hr ; P = ?

P=%280.012%29%2830%5E3%29=%280.012%29%2827000%29
red%28P=324watts%29

Thank you,
Jojo