SOLUTION: Find a number such that four times two more than the number is the same seven less than the opposite of the number.
Algebra ->
Expressions-with-variables
-> SOLUTION: Find a number such that four times two more than the number is the same seven less than the opposite of the number.
Log On
Question 200808: Find a number such that four times two more than the number is the same seven less than the opposite of the number. Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! Let n = the required number, then:
4(n+2) = -n-7
4n+8 = -n-7 Add n to both sides.
5n+8 = -7 Subtract 8 from both sides.
5n = -15 Divide both sides by 5.
n = -3
(