Question 200788: An internal study by the Technology Services department at Lahey Electronics revealed company employees receive an average of two emails per hour. Assume the arrival of these emails is approximated by the Poisson distribution.
a. what is the probability that Linda Lahey, company president, received exactly 1 email between 4pm and 5pm yesterday?
b. what is the probability she received 5 or more email during the same period?
c. what is the probability she did not receive any email during the period?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! An internal study by the Technology Services department at Lahey Electronics revealed company employees receive an average of two emails per hour. Assume the arrival of these emails is approximated by the Poisson distribution.
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lambda = mean of arrivals in a unit of time = 2
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x = # occuring in a give time
P(x arrivals in time interval T) = [e^(-lambda)*(lambda)^x]/x!
a. what is the probability that Linda Lahey, company president, received exactly 1 email between 4pm and 5pm yesterday?
P(1,2) = [e^(-2)*2^1]/1! = 2e^(-2) = 0.2707
Using a TI calculator you would get poissonpdf(2,1) = 0.27069..
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b. what is the probability she received 5 or more email during the same period?
1-poissoncdf(2,4)=0.05265...
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c. what is the probability she did not receive any email during the period?
poissonpdf(2,0) = 0.13534...
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Cheers,
Stan H.
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