SOLUTION: Please help me solve:
The length of a triangle are as follows:
height is 8 feet, base across is 12 feet, what is the lenght of the triangle?
It looks like an isoceles triangle.
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Polynomials-and-rational-expressions
-> SOLUTION: Please help me solve:
The length of a triangle are as follows:
height is 8 feet, base across is 12 feet, what is the lenght of the triangle?
It looks like an isoceles triangle.
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Question 200768: Please help me solve:
The length of a triangle are as follows:
height is 8 feet, base across is 12 feet, what is the lenght of the triangle?
It looks like an isoceles triangle.
Answer:
a=base
b=?
h=height
h=sqrt(b^2-1/4a^2)
8=sqrt(b^2-1/4(12^2)
8=sqrt(b^2-1/4(144)
8=sqrt(b^2-36)
8=b-6
14=b
Please confirm if my answer is ccorrect?
Thanks a bunch Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! height is 8 feet, base across is 12 feet, what is the lenght of the triangle?
It looks like an isoceles triangle.
.
Find the length via the Pythagorean theorem where
length of triangle is the hypotenuse
height is one side
half the base is the other side
.
Let x = length of triangle
8^2 + 6^2 = x^2
64 + 36 = x^2
100 = x^2
sqrt(100) = x
{-10, 10} = x
Throw out negative answer:
10 feet =x
