SOLUTION: 1. X^2+12x+32/X+4*3/x+8 2. 21x^2z^3/6y^3/7xz^3/2y^4 Please help me out. April

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 1. X^2+12x+32/X+4*3/x+8 2. 21x^2z^3/6y^3/7xz^3/2y^4 Please help me out. April      Log On


   

Question 200650: 1. X^2+12x+32/X+4*3/x+8
2. 21x^2z^3/6y^3/7xz^3/2y^4

Please help me out.
April
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
X^2+12x+32/X+4*3/x+8
If you mean
%28%28x%5E2%2B12x%2B32%29%2F%28x%2B4%29%29%2A%283%2F%28x%2B8%29%29
= %28%28x%2B4%29%2A%28x%2B8%29%2F%28x%2B4%29%29%2A%283%2F%28x%2B8%29%29
One step at a time, cancel the (x+4) terms.
= %28%28x%2B8%29%2A3%2F%28x%2B8%29%29
Cancel the (x+8)'s
= 3
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2. 21x^2z^3/6y^3/7xz^3/2y^4
Is it 21x^2z^3/6y^3 divided by 7xz^3/2y^4 ??
Reduce it some first.
21x^2z^3/6y^3 divided by 7xz^3/2y^4
= %287x%5E2z%5E3%2F2y%5E3%29%2F%287xz%5E3%2F2y%5E4%29
Invert the 2nd fraction and multiply
= %287x%5E2z%5E3%2F2y%5E3%29%2A%282y%5E4%2F7xz%5E3%29
You can either multiply, then cancel, or cancel some terms here.
I'll multiply first.
= 14x%5E2y%5E4z%5E3%2F14xy%5E3z%5E3
= xy