SOLUTION: a^2 b+2ab-15b=

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Question 200536: a^2 b+2ab-15b=
Answer by jim_thompson5910(35256) About Me  (Show Source):
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a%5E2b%2B2ab-15b Start with the given expression


b%28a%5E2%2B2a-15%29 Factor out the GCF b


Now let's focus on the inner expression a%5E2%2B2a-15




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Looking at a%5E2%2B2a-15 we can see that the first term is a%5E2 and the last term is -15 where the coefficients are 1 and -15 respectively.

Now multiply the first coefficient 1 and the last coefficient -15 to get -15. Now what two numbers multiply to -15 and add to the middle coefficient 2? Let's list all of the factors of -15:



Factors of -15:
1,3,5,15

-1,-3,-5,-15 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -15
(1)*(-15)
(3)*(-5)
(-1)*(15)
(-3)*(5)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to 2? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 2

First NumberSecond NumberSum
1-151+(-15)=-14
3-53+(-5)=-2
-115-1+15=14
-35-3+5=2



From this list we can see that -3 and 5 add up to 2 and multiply to -15


Now looking at the expression a%5E2%2B2a-15, replace 2a with -3a%2B5a (notice -3a%2B5a adds up to 2a. So it is equivalent to 2a)

a%5E2%2Bhighlight%28-3a%2B5a%29%2B-15


Now let's factor a%5E2-3a%2B5a-15 by grouping:


%28a%5E2-3a%29%2B%285a-15%29 Group like terms


a%28a-3%29%2B5%28a-3%29 Factor out the GCF of a out of the first group. Factor out the GCF of 5 out of the second group


%28a%2B5%29%28a-3%29 Since we have a common term of a-3, we can combine like terms

So a%5E2-3a%2B5a-15 factors to %28a%2B5%29%28a-3%29


So this also means that a%5E2%2B2a-15 factors to %28a%2B5%29%28a-3%29 (since a%5E2%2B2a-15 is equivalent to a%5E2-3a%2B5a-15)



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So our expression goes from b%28a%5E2%2B2a-15%29 and factors further to b%28a%2B5%29%28a-3%29


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Answer:

So a%5E2b%2B2ab-15b completely factors to b%28a%2B5%29%28a-3%29


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